Check the year is leap year or not C program

Check the year is leap year or not C program 

/*
Name   : C source program
Author : Funny Coder(Maniruzzman Akash)
It's a free code. You can use it anywhere
*/


#include <stdio.h>
int main(){
      int year;
      printf("\nEnter any year to check: ");
      scanf("%d", &year);
      if(year % 4 == 0)      //Check devided by 4 or not
      {
          if( year % 100 == 0) 
          {
              if ( year%400 == 0)
                 printf("%d is a leap year.\n", year);
              else
                 printf("%d is not a leap year.\n", year);
          }
          else
             printf("%d is a leap year.\n", year );
      }
      else{
      printf("%d is not a leap year.\n", year);
 }
         
      return 0;
}

Someone think that only devided 4 is a leap year. But that's false. That code is :

#include <stdio.h>
int main(){
      int year;
      printf("\nEnter any year to check: ");
      scanf("%d", &year);
      if(year % 4 == 0)      //Check devided by 4 or not
      {
        printf("%d is a leap year.\n", year );
      }else{
      printf("%d is not a leap year.\n", year);
 }
        
      return 0;
}

The error out put of this code is : 

But 3000 is never be a leap year. So,follow the first code.